Test: Mid Term Exam Semester 2 - Part II ORACLE ACADEMY
by NetPumi2 on January 26th, 2012
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Test: Mid Term Exam Semester 2 - Part II
1. The PRODUCTS table contains these columns:
PRODUCT_ID NUMBER NOT NULL
PRODUCT_NAME VARCHAR2 (25)
SUPPLIER_ID NUMBER NOT NULL
LIST_PRICE NUMBER (7,2)
COST NUMBER (5,2)
QTY_IN_STOCK NUMBER(4)
LAST_ORDER_DT DATE NOT NULL DEFAULT SYSDATE
Which INSERT statement will execute successfully?
INSERT INTO products
VALUES (2958, 'Cable', 8690, 7.09, 4.04, 700);
(*)
INSERT INTO products
VALUES (2958, 'Cable', 8690, 7.09, 4.04, SYSDATE);
INSERT INTO products(product_id, product_name)
VALUES (2958, 'Cable');
INSERT INTO products(product_id, product_name, supplier_id
VALUES (2958, 'Cable', 8690, SYSDATE);
Correct
2. You have been instructed to add a new customer to the CUSTOMERS table. Because the new customer has not had a credit check, you should not add an amount to the CREDIT column.
The CUSTOMERS table contains these columns:
CUST_ID NUMBER(10)
COMPANY VARCHAR2(30)
CREDIT NUMBER(10)
POC VARCHAR2(30)
LOCATION VARCHAR2(30)
Which two INSERT statements will accomplish your objective? Označit pro zhodnocení
(1) Body
(Vyberte všechny správné odpovědi)
INSERT INTO customers (cust_id, company, poc, location)
VALUES (200, 'InterCargo', 'tflanders', 'samerica');
(*)
INSERT INTO customers
VALUES (200, 'InterCargo', null, 'tflanders', 'samerica');
(*)
INSERT INTO customers
VALUES (cust_id, company, credit, poc, location) (200, 'InterCargo', 0, 'tflanders', 'samerica');
INSERT INTO customers
VALUES (200, InterCargo, 0, tflanders, samerica);
Correct
3. Assume all the column names are correct. The following SQL statement will execute which of the following?
INSERT INTO departments (department_id, department_name, manager_id, location_id)
VALUES (70, 'Public Relations', 100, 1700); Označit pro zhodnocení
(1) Body
100 will be inserted into the department_id column
1700 will be inserted into the manager_id column
70 will be inserted into the department_id column (*)
ﾑPublic Relationsﾒ will be inserted into the manager_name column
Correct
4. The STUDENTS table contains these columns:
STU_ID NUMBER(9) NOT NULL
LAST_NAME VARCHAR2 (30) NOT NULL
FIRST_NAME VARCHAR2 (25) NOT NULL
DOB DATE
STU_TYPE_ID VARCHAR2(1) NOT NULL
ENROLL_DATE DATE
You create another table, named FT_STUDENTS, with an identical structure.You want to insert all full-time students, who have a STU_TYPE_ID value of "F", into the new table. You execute this INSERT statement:
INSERT INTO ft_students
(SELECT stu_id, last_name, first_name, dob, stu_type_id, enroll_date
FROM students
WHERE UPPER(stu_type_id) = 'F');
What is the result of executing this INSERT statement? Označit pro zhodnocení
(1) Body
All full-time students are inserted into the FT_STUDENTS table. (*)
An error occurs because the FT_STUDENTS table already exists.
An error occurs because you CANNOT use a subquery in an INSERT statement.
An error occurs because the INSERT statement does NOT contain a VALUES clause.
Correct
5. One of the sales representatives, Janet Roper, has informed you that she was recently married, and she has requested that you update her name in the employee database. Her new last name is Cooper. Janet is the only person with the last name of Roper that is employed by the company. The EMPLOYEES table contains these columns and all data is stored in lowercase:
EMPLOYEE_ID NUMBER(10) PRIMARY KEY
LAST_NAME VARCHAR2(20)
FIRST_NAME VARCHAR2(20)
DEPARTMENT_ID VARCHAR2 (20)
HIRE_DATE DATE
SALARY NUMBER(10)
Which UPDATE statement will accomplish your objective? Označit pro zhodnocení
(1) Body
UPDATE employees
SET last_name = 'cooper'
WHERE last_name = 'roper'; (*)
UPDATE employees last_name = 'cooper'
WHERE last_name = 'roper';
UPDATE employees
SET last_name = 'roper'
WHERE last_name = 'cooper';
UPDATE employees
SET cooper = 'last_name'
WHERE last_name = 'roper';
Correct
6. Examine the structures of the PRODUCTS and SUPPLIERS tables:
SUPPLIERS
SUPPLIER_ID NUMBER NOT NULL, Primary Key
SUPPLIER_NAME VARCHAR2 (25)
ADDRESS VARCHAR2 (30)
CITY VARCHAR2 (25)
REGION VARCHAR2 (10)
POSTAL_CODE VARCHAR2 (11)
PRODUCTS
PRODUCT_ID NUMBER NOT NULL, Primary Key
PRODUCT_NAME VARCHAR2 (25)
SUPPLIER_ID NUMBER Foreign key to SUPPLIER_ID of the SUPPLIERS table
CATEGORY_ID NUMBER
QTY_PER_UNIT NUMBER
UNIT_PRICE NUMBER (7,2)
QTY_IN_STOCK NUMBER
QTY_ON_ORDER NUMBER
REORDER_LEVEL NUMBER
You want to delete any products supplied by the five suppliers located in Atlanta. Which script should you use? Označit pro zhodnocení
(1) Body
DELETE FROM products
WHERE supplier_id IN
(SELECT supplier_id FROM suppliers WHERE UPPER(city) = 'ATLANTA');
(*)
DELETE FROM products
WHERE UPPER(city) = 'ATLANTA';
DELETE FROM products
WHERE supplier_id =
(SELECT supplier_id FROM suppliers WHERE UPPER(city) = 'ATLANTA');
DELETE FROM suppliers
WHERE supplier_id IN
(SELECT supplier_id FROM suppliers WHERE UPPER(city) = 'ALANTA');
Correct
7. Which of the following represents the correct syntax for an INSERT statement? Označit pro zhodnocení
(1) Body
INSERT VALUES INTO customers (3178 J. Smith 123 Main Street Nashville TN 37777;
INSERT INTO customers VALUES '3178' 'J.' 'Smith' '123 Main Street' 'Nashville' 'TN' '37777';
INSERT INTO customers VALUES ('3178', 'J.', 'Smith', '123 Main Street', 'Nashville', 'TN', '37777'); (*)
INSERT customers VALUES 3178, J., Smith, 123 Main Street, Nashville, TN, 37777;
Correct
8. Which two commands can be used to modify existing data in a database row? Označit pro zhodnocení
(1) Body
(Vyberte všechny správné odpovědi)
DELETE
MERGE (*)
SELECT
UPDATE (*)
Correct
9. One of your employees was recently married. Her employee ID is still 189, however, her last name is now Rockefeller. Which SQL statement will allow you to reflect this change? Označit pro zhodnocení
(1) Body
INSERT INTO my_employees SET last_name = 'Rockefeller' WHERE employee_ID = 189;
INSERT my_employees SET last_name = 'Rockefeller' WHERE employee_ID = 189;
UPDATE INTO my_employees SET last_name = 'Rockefeller' WHERE employee_ID = 189;
UPDATE my_employees SET last_name = 'Rockefeller' WHERE employee_ID = 189; (*)
Correct
10. When the WHERE clause is missing in a DELETE statement, what is the result? Označit pro zhodnocení
(1) Body
All rows are deleted from the table. (*)
The table is removed from the database.
An error message is displayed indicating incorrect syntax.
Nothing. The statement will not execute.
Correct
Test: Mid Term Exam Semester 2 - Part II
Projděte své odpovědi, odezvy a hodnocení otázek dole. Hvězdička (*) značí správnou odpověď.
Semester 2 Mid Term Exam Part II covers Sections 5-7 of Database Programming with SQL also.
Section 7
(Odpovězte na všechny otázky v této části)
11. What keyword in an UPDATE statement speficies the columns you want to change? Označit pro zhodnocení
(1) Body
SELECT
WHERE
SET (*)
HAVING
Correct
12. You need to update the expiration date of products manufactured before June 30th . In which clause of the UPDATE statement will you specify this condition? Označit pro zhodnocení
(1) Body
The ON clause
The WHERE clause (*)
The SET clause
The USING clause
Correct
13. Aliases can be used with MERGE statements. True or False? Označit pro zhodnocení
(1) Body
True (*)
False
Correct
14. Multi-table inserts are used when the same source data should be inserted into _____________ target table. Označit pro zhodnocení
(1) Body
Ten
A very large
More than one (*)
A data warehouse
Correct
Section 6
(Odpovězte na všechny otázky v této části)
15. The Oracle server performs a correlated subquery when the subquery references a column from a table referred to in the parent. True or False? Označit pro zhodnocení
(1) Body
True (*)
False
Correct
16. A correlated subquery will _______ a candidate row from an outer query, _______ the inner query using candidate row value, and _______ values from the inner query to qualify or disqualify the candidate row. Označit pro zhodnocení
(1) Body
CREATE; EXECUTE; USE
DELETE; UPDATE; INSERT
GET; EXECUTE; USE (*)
ROLLUP; GRANT; DROP
Incorrect. Refer to Section 6 Lesson 4.
17. The WITH clause enables a SELECT statement to define the subquery block at the start of the query, process the block just once, label the results, and then refer to the results multiple times. True or False? Označit pro zhodnocení
(1) Body
True (*)
False
Correct
18. Which statement is false? Označit pro zhodnocení
(1) Body
The WITH clause retrieves the results of one or more query blocks
The WITH clause decreases performance (*)
The WITH clause makes the query simple to read
The WITH clause stores the results for the user who runs the query
Correct
19. Examine the data in the PAYMENT table:
>>>>
PAYMENT_ID CUSTOMER_ID PAYMENT_DATE PAYMENT_TYPE PAYMENT_AMOUNT
86590586 8908090 10-JUN-03 BASIC 859.00
89453485 8549038 15-FEB-03 INTEREST 596.00
85490345 5489304 20-MAR-03 BASIC 568.00
This statement fails when executed:
SELECT payment_date, customer_id, payment_amount
FROM payment
WHERE payment_id =
(SELECT payment_id
FROM payment
WHERE payment_date >= '05-JAN-2002' OR payment_amount > 500.00);
Which change could correct the problem? Označit pro zhodnocení
(1) Body
Remove the subquery WHERE clause.
Change the outer query WHERE clause to 'WHERE payment_id IN'. (*)
Include the PAYMENT_ID column in the select list of the outer query.
Remove the single quotes around the date value in the inner query WHERE clause.
Correct
20. Evaluate this SELECT statement:
SELECT player_id, name
FROM players
WHERE team_id IN
(SELECT team_id
FROM teams
WHERE team_id > 300 AND salary_cap > 400000);
What would happen if the inner query returned a NULL value? Označit pro zhodnocení
(1) Body
No rows would be returned by the outer query. (*)
A syntax error in the outer query would be returned.
A syntax error in the inner query would be returned.
All the rows in the PLAYER table would be returned by the outer query.
Correct
Stránka 2 z 5
Test: Mid Term Exam Semester 2 - Part II
Projděte své odpovědi, odezvy a hodnocení otázek dole. Hvězdička (*) značí správnou odpověď.
Semester 2 Mid Term Exam Part II covers Sections 5-7 of Database Programming with SQL also.
Section 6
(Odpovězte na všechny otázky v této části)
21. Which statement about the ANY operator when used with a multiple-row subquery is true? Označit pro zhodnocení
(1) Body
The ANY operator compares every value returned by the subquery. (*)
The ANY operator can be used with the DISTINCT keyword.
The ANY operator is a synonym for the ALL operator.
The ANY operator can be used with the LIKE and IN operators.
Correct
22. If a single-row subquery returns a null value and uses the equality comparison operator, what will the outer query return? Označit pro zhodnocení
(1) Body
No rows (*)
All the rows in the table
A null value
An error
Correct
23. Which statement about the <> operator is true? Označit pro zhodnocení
(1) Body
The <> operator is NOT a valid SQL operator.
The <> operator CANNOT be used in a single-row subquery.
The <> operator returns the same result as the ANY operator in a subquery.
The <> operator can be used when a single-row subquery returns only one row. (*)
Correct
24. Which statement about subqueries is true? Označit pro zhodnocení
(1) Body
Subqueries should be enclosed in double quotation marks.
Subqueries cannot contain group functions.
Subqueries are often used in a WHERE clause to return values for an unknown conditional value. (*)
Subqueries generally execute last, after the main or outer query executes.
Correct
25. The EMPLOYEES and ORDERS tables contain these columns:
EMPLOYEES
EMPLOYEE_ID NUMBER(10) NOT NULL PRIMARY KEY
FIRST_NAME VARCHAR2(30)
LAST_NAME VARCHAR2(30)
ADDRESS VARCHAR2(25)
CITY VARCHAR2(20)
STATE VARCHAR2(2)
ZIP NUMBER(9)
TELEPHONE NUMBER(10)
ORDERS
ORDER_ID NUMBER(10) NOT NULL PRIMARY KEY
EMPLOYEE_ID NUMBER(10) NOT NULL FOREIGN KEY
ORDER_DATE DATE
TOTAL NUMBER(10)
Which SELECT statement will return all orders generated by a sales representative named Franklin during the year 2001? Označit pro zhodnocení
(1) Body
SELECT order_id, total
FROM ORDERS (SELECT employee_id
FROM employees
WHERE last_name = 'Franklin')
WHERE order_date BETWEEN '01-jan-01' AND '31-dec-01';
SELECT (SELECT employee_id FROM employees WHERE last_name = 'Franklin') AND order_id, total
FROM ORDERS
WHERE order_date BETWEEN '01-jan-01' AND '31-dec-01';
SELECT order_id, employee_id, total
FROM ORDERS
WHERE order_date BETWEEN '01-jan-01' AND '31-dec-01' AND emp_id = 'Franklin';
SELECT order_id, total
FROM ORDERS
WHERE employee_id = (SELECT employee_id FROM employees WHERE last_name = 'Franklin')
AND order_date BETWEEN '01-jan-01' AND '31-dec-01';
(*)
Correct
26. The TEACHERS and CLASS_ASSIGNMENTS tables contain these columns:
TEACHERS
TEACHER_ID NUMBER(5) Primary Key
NAME VARCHAR2 (25)
SUBJECT_ID NUMBER(5)
CLASS_ASSIGNMENTS
CLASS_ID NUMBER (5) Primary Key
TEACHER_ID NUMBER (5)
DATE
MAX_CAPACITY NUMBER (3)
All MAX_CAPACITY values are greater than 10. Which two SQL statements correctly use subqueries? (Choose two.) Označit pro zhodnocení
(1) Body
(Vyberte všechny správné odpovědi)
SELECT *
FROM class_assignments
WHERE max_capacity = (SELECT AVG(max_capacity) FROM class_assignments);
(*)
SELECT *
FROM teachers
WHERE teacher_id = (SELECT teacher_id FROM teachers WHERE class_id = 45963);
(*)
SELECT *
FROM teachers
WHERE teacher_id = (SELECT teacher_id, class_assignments WHERE max_capacity > 0);
SELECT *
FROM teachers
WHERE teacher_id LIKE (SELECT teacher_id FROM class_assignments WHERE max_capacity > 1000);
SELECT *
FROM class_assignments
max_capacity = (SELECT AVG(max_capacity) FROM class_assignments GROUP BY teacher_id);
Correct
27. Which operator can be used with a multiple-row subquery? Označit pro zhodnocení
(1) Body
IN (*)
<>
=
LIKE
Correct
28. Using a subquery in which clause will return a syntax error? Označit pro zhodnocení
(1) Body
WHERE
FROM
HAVING
You can use subqueries in all of the above clauses. (*)
Correct
29. Which operator can be used with subqueries that return only one row? Označit pro zhodnocení
(1) Body
LIKE (*)
ANY
ALL
IN
Correct
30. Which of the following is TRUE regarding the order of subquery execution? Označit pro zhodnocení
(1) Body
The outer query is executed first
The subquery executes once after the main query
The subquery executes once before the main query (*)
The result of the main query is used with the subquery
Correct
Stránka 3 z 5
Test: Mid Term Exam Semester 2 - Part II
Projděte své odpovědi, odezvy a hodnocení otázek dole. Hvězdička (*) značí správnou odpověď.
Semester 2 Mid Term Exam Part II covers Sections 5-7 of Database Programming with SQL also.
Section 6
(Odpovězte na všechny otázky v této části)
31. You need to create a report to display the names of products with a cost value greater than the average cost of all products. Which SELECT statement should you use? Označit pro zhodnocení
(1) Body
SELECT product_name
FROM products
WHERE cost > (SELECT AVG(cost)
FROM product);
(*)
SELECT product_name
FROM products
WHERE cost > AVG(cost);
SELECT AVG(cost), product_name
FROM products
WHERE cost > AVG(cost)
GROUP by product_name;
SELECT product_name
FROM (SELECT AVG(cost) FROM product)
WHERE cost > AVG(cost);
Correct
Section 5
(Odpovězte na všechny otázky v této části)
32. You use ROLLUP to: Označit pro zhodnocení
(1) Body
produce subtotal values (*)
cross-tabulate values
produce a single result set
Correct
33. CUBE can be applied to all aggregate functions including AVG, SUM, MIN, MAX, and COUNT. True or False? Označit pro zhodnocení
(1) Body
True (*)
False
Correct
34. You use GROUPING function to: Označit pro zhodnocení
(1) Body
Produce subtotal and cross-tabulated values
Identify the extra row values created by either a ROLLUP or CUBE operation (*)
Aggregate rows using SUM, MIN, MAX, and COUNT
Correct
35. You use GROUPING function to ______ database rows from tabulated rows. Označit pro zhodnocení
(1) Body
CREATE
DISTINGUISH (*)
COMPUTE
COUNT
Correct
36. The PRODUCTS table contains these columns:
PRODUCT_ID NUMBER(9) PK
CATEGORY_ID VARCHAR2(10)
LOCATION_ID NUMBER(9)
DESCRIPTION VARCHAR2(30)
COST NUMBER(7,2)
PRICE NUMBER(7,2)
QUANTITY NUMBER
You display the total of the extended costs for each product category by location.
You need to include only the products that have a price less than $25.00.
The extended cost of each item equals the quantity value multiplied by the cost value.
Which SQL statement will display the desired result? Označit pro zhodnocení
(1) Body
SELECT category_id, SUM(cost * quantity) TOTAL,location_id
FROM products
WHERE price > 25.00
GROUP BY category_id, location_id;
SELECT SUM(cost * quantity) TOTAL, location_id
FROM products
WHERE price < 25.00 <br /> GROUP BY location_id;
SELECT category_id, SUM(cost * quantity) TOTAL, location_id
FROM products
WHERE price < 25.00 <br /> GROUP BY category_id, location_id;
(*)
SELECT SUM(cost * quantity) TOTAL
FROM products
WHERE price < 25.00;
Correct
37. The PRODUCTS table contains these columns:
PROD_ID NUMBER(4)
PROD_NAME VARCHAR(20)
PROD_CAT VARCHAR2(15)
PROD_PRICE NUMBER(5)
PROD_QTY NUMBER(4)
You need to identify the minimum product price in each product category.
Which statement could you use to accomplish this task? Označit pro zhodnocení
(1) Body
SELECT prod_cat, MIN (prod_price)
FROM products
GROUP BY prod_price;
SELECT prod_cat, MIN (prod_price)
FROM products
GROUP BY prod_cat;
(*)
SELECT MIN (prod_price), prod_cat
FROM products
GROUP BY MIN (prod_price), prod_cat;
SELECT prod_price, MIN (prod_cat)
FROM products
GROUP BY prod_cat;
Correct
38. The PLAYERS and TEAMS tables contain these columns:
PLAYERS
PLAYER_ID NUMBER NOT NULL, PRIMARY KEY
LAST_NAME VARCHAR2 (30) NOT NULL
FIRST_NAME VARCHAR2 (25) NOT NULL
TEAM_ID NUMBER
POSITION VARCHAR2 (25)
TEAMS
TEAM_ID NUMBER NOT NULL, PRIMARY KEY
TEAM_NAME VARCHAR2 (25)
You need to create a report that lists the names of each team with more than three goal keepers.
Which SELECT statement will produce the desired result? Označit pro zhodnocení
(1) Body
SELECT t.team_name, COUNT(p.player_id)
FROM players p, teams t
ON (p.team_id = t.team_id)
WHERE UPPER(p.position) = 'GOAL KEEPER'
GROUP BY t.team_name;
SELECT t.team_name, COUNT(p.player_id)
FROM players
JOIN teams t ON (p.team_id = t.team_id)
WHERE UPPER(p.position) = 'GOAL KEEPER'
HAVING COUNT(p.player_id) > 3;
SELECT t.team_name, COUNT(p.player_id)
FROM players p, teams t
ON (p.team_id = t.team_id)
WHERE UPPER(p.position) = 'GOAL KEEPER'
GROUP BY t.team_name
HAVING COUNT(p.player_id) > 3;
SELECT t.team_name, COUNT(p.player_id)
FROM players p
JOIN teams t ON (p.team_id = t.team_id)
WHERE UPPER(p.position) = 'GOAL KEEPER'
GROUP BY t.team_name
HAVING COUNT(p.player_id) > 3;
(*)
Correct
39. Evaluate this SELECT statement:
SELECT SUM(salary), department_id, manager_id
FROM employees
GROUP BY department_id, manager_id;
Which SELECT clause allows you to restrict the rows returned, based on a group function? Označit pro zhodnocení
(1) Body
HAVING SUM(salary) > 100000 (*)
WHERE SUM(salary) > 100000
WHERE salary > 100000
HAVING salary > 100000
Correct
40. Evaluate this SELECT statement:
SELECT MAX(salary), department_id
FROM employees
GROUP BY department_id;
Which values are displayed? Označit pro zhodnocení
(1) Body
The highest salary for all employees.
The highest salary in each department. (*)
The employees with the highest salaries.
The employee with the highest salary for each department.
Correct
Stránka 4 z 5
Test: Mid Term Exam Semester 2 - Part II
Projděte své odpovědi, odezvy a hodnocení otázek dole. Hvězdička (*) značí správnou odpověď.
Semester 2 Mid Term Exam Part II covers Sections 5-7 of Database Programming with SQL also.
Section 5
(Odpovězte na všechny otázky v této části)
41. Evaluate this SELECT statement:
SELECT COUNT(employee_id), department_id
FROM employees
GROUP BY department_id;
You only want to include employees who earn more than 15000.
Which clause should you include in the SELECT statement? Označit pro zhodnocení
(1) Body
WHERE salary > 15000 (*)
HAVING salary > 15000
WHERE SUM(salary) > 15000
HAVING SUM(salary) > 15000
Correct
42. What is the correct order of clauses in a SELECT statement? Označit pro zhodnocení
(1) Body
SELECT
FROM
WHERE
ORDER BY
GROUP BY
HAVING
SELECT
FROM
HAVING
GROUP BY
WHERE
ORDER BY
SELECT
FROM
WHERE
GROUP BY
HAVING
ORDER BY
(*)
SELECT
FROM
WHERE
HAVING
ORDER BY
GROUP BY
Correct
43. The EMPLOYEES table contains these columns:
ID_NUMBER NUMBER Primary Key
NAME VARCHAR2 (30)
DEPARTMENT_ID NUMBER
SALARY NUMBER (7,2)
HIRE_DATE DATE
Evaluate this SQL statement:
SELECT id_number, name, department_id, SUM(salary)
FROM employees
WHERE salary > 25000
GROUP BY department_id, id_number, name
ORDER BY hire_date;
Why will this statement cause an error? Označit pro zhodnocení
(1) Body
The HAVING clause is missing.
The WHERE clause contains a syntax error.
The SALARY column is NOT included in the GROUP BY clause.
The HIRE_DATE column is NOT included in the GROUP BY clause. (*)
Correct
44. Evaluate this statement:
SELECT department_id, AVG(salary)
FROM employees
WHERE job_id <> 69879
GROUP BY job_id, department_id
HAVING AVG(salary) > 35000
ORDER BY department_id;
Which clauses restricts the result? Choose two. Označit pro zhodnocení
(1) Body
(Vyberte všechny správné odpovědi)
SELECT department_id, AVG(salary)
WHERE job_id <> 69879 (*)
GROUP BY job_id, department_id
HAVING AVG(salary) > 35000 (*)
Correct
45. Which statement about group functions is true? Označit pro zhodnocení
(1) Body
Group functions ignore null values. (*)
Group functions can only be used in a SELECT list.
Group functions can be used in a WHERE clause.
A query that includes a group function in the SELECT list must include a GROUP BY clause.
Correct
46. The PAYMENT table contains these columns:
PAYMENT_ID NUMBER(9) PK
PAYMENT_DATE DATE
CUSTOMER_ID NUMBER(9)
Which SELECT statement could you use to display the number of times each customer payment was made between January 1, 2003 and June 30, 2003 ? Označit pro zhodnocení
(1) Body
SELECT customer_id, COUNT(payment_id)
FROM payment
WHERE payment_date BETWEEN '01-JAN-2003' AND '30-JUN-2003'
GROUP BY customer_id;
(*)
SELECT COUNT(payment_id)
FROM payment
WHERE payment_date BETWEEN '01-JAN-2003' AND '30-JUN-2003';
SELECT customer_id, COUNT(payment_id)
FROM payment
WHERE payment_date BETWEEN '01-JAN-2003' AND '30-JUN-2003';
SELECT COUNT(payment_id)
FROM payment
WHERE payment_date BETWEEN '01-JAN-2003' AND '30-JUN-2003'
GROUP BY customer_id;
Correct
47. What is the best explanation as to why this SQL statement will NOT execute?
SELECT department_id "Department", AVG (salary)"Average"
FROM employees
GROUP BY Department; Označit pro zhodnocení
(1) Body
Salaries cannot be averaged as not all the numbers will divide evenly.
You cannot use a column alias in the GROUP BY clause. (*)
The GROUP BY clause must have something to GROUP.
The department id is not listed in the departments table.
Correct
48. The PLAYERS table contains these columns:
PLAYER_ID NUMBER PK
PLAYER_NAME VARCHAR2 (30)
TEAM_ID NUMBER
HIRE_DATE DATE
SALARY NUMBER (8,2)
Which clauses represent valid uses of aggregate functions? (Choose three.) Označit pro zhodnocení
(1) Body
(Vyberte všechny správné odpovědi)
ORDER BY AVG(salary) (*)
GROUP BY MAX(salary)
SELECT AVG(NVL(salary, 0)) (*)
HAVING MAX(salary) > 10000 (*)
WHERE hire_date > AVG(hire_date)
Correct
49. To control the order of rows returned using SET operators, the ORDER BY clause is used ______ and is placed in the _____ SELECT statement of the query. Označit pro zhodnocení
(1) Body
ONCE; FIRST
TWICE; FIRST
ONCE; LAST (*)
IN ALL; LAST
Correct
50. When using SET operators the number of columns and the data types of the columns must be identical in all of the SELECT statements used in the query. True or False. Označit pro zhodnocení
(1) Body
True (*)
False
Incorrect. Refer to Section 5 Lesson 3.
Stránka 5 z 5
موضوع: Test: Mid Term Exam Semester 2 - Part II 
الأربعاء 30 مايو 2012, 14:42
